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The second order derivative of the function y=log⁡(4x3+6)y=\log(4x^3+6) with respect to 'x' will be:

Solution

✅ Correct Option: 2

dydx=12x24x3+6=6x22x3+3\frac{dy}{dx}=\frac{12x^2}{4x^3+6}=\frac{6x^2}{2x^3+3}.

By the quotient rule, d2ydx2=12x(2x3+3)−6x2(6x2)(2x3+3)2=36x−12x4(2x3+3)2=12x(3−x3)(2x3+3)2\frac{d^2y}{dx^2}=\frac{12x(2x^3+3)-6x^2(6x^2)}{(2x^3+3)^2}=\frac{36x-12x^4}{(2x^3+3)^2}=\frac{12x(3-x^3)}{(2x^3+3)^2}.

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