The Solution set of the inequality three $3x + 4y \leq 12$ is :

Objective function $Z = 200x + 500y$, subject to constraint, $x + 2y \geq 10, 3x + 4y \leq 24$, $x \geq 0, y \geq 0$ - (iii), the minimum value of Z is :

Corner points of the feasible region for an LPP are : (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). Let $z = 4x + 6y$ be the objective function. Then, Max z $-$ Min z is equal to :

Match List I with List II

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The feasible region for an LPP is shown in the figure given below: If objective is maximizing $Z = 22x + 18y$ find $(x, y)$ for the optimal $Z$.

The bounded feasible region of an LPP is shown in the diagram given below.

The objective function $z=3x+10y$ attains optimum values at :

A. Point (0,0)

B. Point (0,4)

C. Point (6,3)

D. Point (5,6)

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For the feasible reason of a LPP as shown, if the equation of OA and BC are $y - 2x = 0$ and $y - 2x = 4$ respectively than constraints for LPP are