CUET Mathematics - Match the LIST-I with LIST-II | | LIST-I (Inequality) | | LIST-II (Solution set) | |---|---|---|---| | A. | x-3 < 1 | I. | x (-2/5, 8/5) | | B. | 3-5x < 5 | II. | x (-∞, -1/2) | | C. | 2x+1 < 2x+1 | III. | x (-1/3, 5) | | D. | 7-3x < 8 | IV. | x (2,4) | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 18th May Shift 2

Algebra

Medium

applied

A-I, B-II, C-III, D-IV

A-II, B-IV, C-I, D-III

A-I, B-IV, C-III, D-II

A-IV, B-I, C-II, D-III

✅ Correct Option: 4

Related questions:

21st May Shift 1

Which one of the following inequalities are satisfied by $x = 10$ ?

19 May Shift 1

Match List-I with List-II

List-I	List-II
(Inequality)	(Solution Set)
---	---
(A) $2x - 3 < x + 2 \le 3x + 5, x \in \mathbb{R}$	(I) $x \in (-1, \infty)$
(B) $\vert 2x + 3\vert < 7, x \in \mathbb{R}$	(II) $x \in (-\infty, 120]$
(C) $\frac{1}{2}\left(\frac{3}{5}x + 4\right) \ge \frac{1}{3}(x - 6), x \in \mathbb{R}$	(III) $x \in (-5, 2)$
(D) $\frac{\vert x + 1\vert }{x + 1} > 0, x \in \mathbb{R} - \{-1\}$	(IV) $x \in \left[-\frac{3}{2}, 5\right)$

Choose the correct answer from the options given below:

30th May Shift 2

Match List-I with List-II

List-I	List-II
(A) The solution set of the inequation $3x-6\le 0$ is	(I) $(3,\infty)$
(B) The solution set of the inequation $-5x+20<0$ is	(II) $[3,\infty)$
(C) The solution set of the inequation $3x-9\ge 0$ is	(III) $(-\infty,2]$
(D) The solution set of the inequation $8x+11>35$ is	(IV) $(4,\infty)$

Choose the correct answer from the options given below:

CUET Mathematics 2026 18th May Shift 2 PYQs