Skip to main contentSkip to solution

If A=[0b−ac−aa−b0c−ba−cb−c0]A=\begin{bmatrix}0 & b-a & c-a\\a-b & 0 & c-b\\a-c & b-c & 0\end{bmatrix} then the value of ∣A∣\lvert A \rvert is

Solution

✅ Correct Option: 3

Each pair satisfies aij=−ajia_{ij}=-a_{ji}, for example b−ab-a and a−ba-b, so AA is skew-symmetric of order 33.

For odd order, ∣A∣=∣AT∣=∣−A∣=(−1)3∣A∣|A|=|A^T|=|-A|=(-1)^3|A|, forcing ∣A∣=0|A|=0.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question