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The angle between the planes 2x+y+3z−2=02x + y + 3z - 2 = 0 and x−2y+5=0x - 2y + 5 = 0 is :

Solution

✅ Correct Option: 2

Normals: n1⃗=(2,1,3)\vec{n_1} = (2,1,3), n2⃗=(1,−2,0)\vec{n_2} = (1,-2,0). Dot product =2−2+0=0= 2-2+0 = 0. Since dot product is zero, the planes are perpendicular, so the angle is 90°90°.

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