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If y=log⁡e(5x2)5y=\sqrt[5]{\log_e(5x^2)}, then dydx=\dfrac{dy}{dx}=

(Take log⁡ex=log⁡x\log_e x=\log x)

Solution

✅ Correct Option: 1

Write y=[log⁡(5x2)]1/5y = [\log(5x^2)]^{1/5} and apply the chain rule:

dydx=15[log⁡(5x2)]−4/5⋅15x2⋅10x=15[log⁡(5x2)]−4/5⋅2x\dfrac{dy}{dx} = \dfrac{1}{5}[\log(5x^2)]^{-4/5}\cdot\dfrac{1}{5x^2}\cdot 10x = \dfrac{1}{5}[\log(5x^2)]^{-4/5}\cdot\dfrac{2}{x}.

This equals 25x[log⁡(5x2)]4/5\dfrac{2}{5x[\log(5x^2)]^{4/5}}.

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