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If A and B are independent events such that P(A)=12P(A)=\dfrac{1}{2}, P(A∪B)=35P(A\cup B)=\dfrac{3}{5} and P(B)=pP(B)=p, then value of p is:

Solution

✅ Correct Option: 2

For independent events, P(A∪B)=P(A)+P(B)−P(A)P(B)P(A\cup B) = P(A) + P(B) - P(A)P(B).

So 35=12+p−p2=12+p2\dfrac{3}{5} = \dfrac{1}{2} + p - \dfrac{p}{2} = \dfrac{1}{2} + \dfrac{p}{2}.

Thus p2=110\dfrac{p}{2} = \dfrac{1}{10} and p=15p = \dfrac{1}{5}.

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