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If P(r⃗)P(\vec{r}) is a position vector of a point with scalar components (x,y,z)(x,y,z), then the value of (r⃗.i^)(−i^)−(r⃗.j^)j^+(r⃗.(−k^))k^(\vec{r}.\hat{i})(-\hat{i})-(\vec{r}.\hat{j})\hat{j}+(\vec{r}.(-\hat{k}))\hat{k}, is:

Solution

✅ Correct Option: 4

Here r⃗⋅i^=x\vec{r}\cdot\hat{i} = x, r⃗⋅j^=y\vec{r}\cdot\hat{j} = y and r⃗⋅(−k^)=−z\vec{r}\cdot(-\hat{k}) = -z.

Substituting gives x(−i^)−yj^+(−z)k^=−xi^−yj^−zk^x(-\hat{i}) - y\hat{j} + (-z)\hat{k} = -x\hat{i} - y\hat{j} - z\hat{k}.

This is −(xi^+yj^+zk^)-(x\hat{i}+y\hat{j}+z\hat{k}).

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