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For the function (ex)y=ex(ex)^y=e^x;

Match the LIST-I with LIST-II

LIST-ILIST-II
A. yy is equal toI. 1−log⁡exx(1+log⁡ex)3\dfrac{1-\log_e x}{x(1+\log_e x)^3}
B. value of dydx\dfrac{dy}{dx}II. x1+log⁡ex\dfrac{x}{1+\log_e x}
C. value of d2ydx2\dfrac{d^2y}{dx^2}III. log⁡ex(1+log⁡ex)2\dfrac{\log_e x}{(1+\log_e x)^2}
D. xyx^y is equal toIV. ex−ye^{x-y}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Taking logarithms, y(1+log⁡ex)=xy(1+\log_e x) = x, so y=x1+log⁡exy = \dfrac{x}{1+\log_e x} (II).

Differentiating by the quotient rule, dydx=log⁡ex(1+log⁡ex)2\dfrac{dy}{dx} = \dfrac{\log_e x}{(1+\log_e x)^2} (III).

Differentiating again gives 1−log⁡exx(1+log⁡ex)3\dfrac{1-\log_e x}{x(1+\log_e x)^3} (I).

From eyxy=exe^y x^y = e^x, xy=ex−yx^y = e^{x-y} (IV).

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