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Match the LIST-I with LIST-II

LIST-I FunctionsLIST-II Principal value
A. sin⁡−1(12)\sin^{-1}\left(\dfrac{1}{2}\right)I. π4\dfrac{\pi}{4}
B. sin⁡−1(−12)\sin^{-1}\left(-\dfrac{1}{\sqrt{2}}\right)II. π6\dfrac{\pi}{6}
C. tan⁡−1(1)\tan^{-1}(1)III. −π4-\dfrac{\pi}{4}
D. cos⁡−1(−12)\cos^{-1}\left(-\dfrac{1}{2}\right)IV. 2π3\dfrac{2\pi}{3}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Using principal value branches:

sin⁡−1(1/2)=π/6\sin^{-1}(1/2) = \pi/6 (II).

sin⁡−1(−1/2)=−π/4\sin^{-1}(-1/\sqrt{2}) = -\pi/4 (III), since the range is [−π/2,π/2][-\pi/2,\pi/2].

tan⁡−1(1)=π/4\tan^{-1}(1) = \pi/4 (I).

cos⁡−1(−1/2)=π−π/3=2π/3\cos^{-1}(-1/2) = \pi - \pi/3 = 2\pi/3 (IV), since the range is [0,π][0,\pi].

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