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If A=[10−15]A=\begin{bmatrix} 1 & 0 \\ -1 & 5 \end{bmatrix} and I is indentity matrix of order 2, then which of following statements are TRUE?

A. A2−6A−mI=0A^2-6A-mI=0 if m=−5m=-5.

B. A2−6A+mI=0A^2-6A+mI=0 if m=−5m=-5.

C. AA is a non-singular matrix.

D. A2=AA^2=A

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

A2=[10−625]A^2 = \begin{bmatrix} 1 & 0 \\ -6 & 25 \end{bmatrix} and 6A=[60−630]6A = \begin{bmatrix} 6 & 0 \\ -6 & 30 \end{bmatrix}, so A2−6A=−5IA^2 - 6A = -5I.

With m=−5m=-5, statement A reads A2−6A+5I=0A^2-6A+5I=0, which is true; statement B reads A2−6A−5I=0A^2-6A-5I=0, which is false.

∣A∣=5≠0|A| = 5 \ne 0, so C is true. A2≠AA^2 \ne A, so D is false.

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