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The integrating factor of the differential equation ylog⁡e(10y).dxdy+x=1[log⁡e(10y)]2y\log_e(10y).\dfrac{dx}{dy}+x=\dfrac{1}{[\log_e(10y)]^2}, is

Solution

✅ Correct Option: 2

Divide throughout by ylog⁡e(10y)y\log_e(10y) to get the linear form dxdy+xylog⁡e(10y)=Q(y)\dfrac{dx}{dy} + \dfrac{x}{y\log_e(10y)} = Q(y).

The integrating factor is e∫dyylog⁡e(10y)e^{\int \frac{dy}{y\log_e(10y)}}. Putting u=log⁡e(10y)u = \log_e(10y) gives du=dy/ydu = dy/y, so the integral is log⁡eu\log_e u.

Hence the integrating factor is log⁡e(10y)\log_e(10y).

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