Skip to main contentSkip to solution

The value of λ\lambda for which the following system of equations has no solution is

x+y+2z=4x+y+2z=4

2x+y+3z=52x+y+3z=5

x+3y+λz=7x+3y+\lambda z=7

Solution

✅ Correct Option: 1

For no solution the coefficient determinant must vanish.

∣11221313λ∣=(λ−9)−(2λ−3)+2(5)=4−λ=0\begin{vmatrix}1&1&2\\2&1&3\\1&3&\lambda\end{vmatrix} = (\lambda-9)-(2\lambda-3)+2(5) = 4-\lambda = 0, so λ=4\lambda = 4.

Substituting λ=4\lambda=4 makes the third equation inconsistent with the first two, confirming there is no solution.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question