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A value of xx satisfying 6x≡5(mod7)6x \equiv 5 \pmod{7} is

Solution

✅ Correct Option: 1

Since 6≡−1(mod7)6\equiv -1 \pmod 7, the congruence becomes −x≡5-x\equiv 5, that is x≡−5≡2(mod7)x\equiv -5 \equiv 2 \pmod 7.

Checking the options, x=−5x=-5 works because 6(−5)=−306(-5) = -30 and −30−5=−35-30 - 5 = -35 is divisible by 7.

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