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If [x−2yz3x+yw]=[12−111]\begin{bmatrix} x-2y & z \\ 3x+y & w \end{bmatrix}=\begin{bmatrix} 1 & 2 \\ -11 & 1 \end{bmatrix}; then the value of y−xy-x is:-

Solution

✅ Correct Option: 1

Equating corresponding entries gives x−2y=1x-2y=1 and 3x+y=−113x+y=-11.

From the first, x=1+2yx = 1+2y. Substituting: 3+6y+y=−113+6y+y=-11, so y=−2y=-2 and x=−3x=-3.

Hence y−x=−2−(−3)=1y-x = -2-(-3) = 1.

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