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If a⃗\vec{a} and b⃗\vec{b} are two non-zero vectors such that ∣2a⃗+b⃗∣=∣b⃗∣|2\vec{a}+\vec{b}|=|\vec{b}| and a⃗+b⃗≠0⃗\vec{a}+\vec{b}\ne \vec{0}, then the angle between a⃗+b⃗\vec{a}+\vec{b} and a⃗\vec{a}, is

Solution

✅ Correct Option: 3

Squaring the given condition: 4∣a⃗∣2+4a⃗⋅b⃗+∣b⃗∣2=∣b⃗∣24|\vec{a}|^2 + 4\vec{a}\cdot\vec{b} + |\vec{b}|^2 = |\vec{b}|^2, so a⃗⋅b⃗=−∣a⃗∣2\vec{a}\cdot\vec{b} = -|\vec{a}|^2.

Then (a⃗+b⃗)⋅a⃗=∣a⃗∣2+a⃗⋅b⃗=0(\vec{a}+\vec{b})\cdot\vec{a} = |\vec{a}|^2 + \vec{a}\cdot\vec{b} = 0.

Since neither vector is zero, the angle is 90∘90^\circ.

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