P(X = x) = cases 2k & if x = 0 \\ kx & if x = 1 \\ k(x - 1) & if x = 2 or 3 \\ 0 & otherwise cases The value of k is Option 1: 1/4 Option 2: 1/6 Option 3: 2/3 Option 4: 6

The answer is '1/6'. View full solution:

CUET Mathematics - P(X = x) = cases 2k & if x = 0 \\ kx & if x = 1 \\ k(x - 1) & if x = 2 or 3 \\ 0 & otherwise cases The value of k is | PYQs + Solutions

CUET Mathematics 2023 11 Aug Shift 1

Applied Mathematics

Medium

$\frac{1}{4}$

$\frac{1}{6}$

$\frac{2}{3}$

✅ Correct Option: 2

Related questions:

25 May Shift 1

If the probability distribution of a discrete random variable $X$ is given as

X	0	1	2	3	4
P(X)	0.5	2k	3k	3k	2k

Then the value of $k$ is:

7 June Shift 1

Match list I with list II. 4 defective pens are mixed with 10 normal pens. 3 pens are drawn one by one with replacement , then the probability distribution of the number of defective pens is :

List-I	List - II
A. P(X=0)	8/343
B. P(X=1)	60/343
C. P(X=2)	125/343
D. P(X=3)	150/343

Choose the correct option below :

11 Aug Shift 1

A random variable X has a probability distribution P(X) of the following form, where k is some unknown constant:

P(X = 0) = k

P(X = 1) = 2k

P(X = 2) = 3k

P(X = other values) = 0

Then, find the value of 1/k.

CUET Mathematics 2023 11 Aug Shift 1 PYQs

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