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If a⃗\vec{a} is a unit vector and (x⃗−a⃗)⋅(x⃗+a⃗)=8(\vec{x} - \vec{a}) \cdot (\vec{x} + \vec{a}) = 8 then ∣x⃗∣|\vec{x}| is

Solution

✅ Correct Option: 2

(x⃗−a⃗)⋅(x⃗+a⃗)=∣x⃗∣2−∣a⃗∣2=∣x⃗∣2−1=8(\vec{x} - \vec{a})\cdot(\vec{x} + \vec{a}) = |\vec{x}|^2 - |\vec{a}|^2 = |\vec{x}|^2 - 1 = 8. So ∣x⃗∣2=9|\vec{x}|^2 = 9, hence ∣x⃗∣=3|\vec{x}| = 3.

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