Skip to main contentSkip to solution

The order of 1+(dydx)2=[ad2ydx2]12\sqrt{1 + \left(\frac{dy}{dx}\right)^2} = \left[a \frac{d^2y}{dx^2}\right]^{\frac{1}{2}} is

Solution

✅ Correct Option: 2

Given equation:

1+(dydx)2=[ad2ydx2]12\sqrt{1 + \left(\frac{dy}{dx}\right)^2} = \left[a \frac{d^2y}{dx^2}\right]^{\frac{1}{2}}


The order of a differential equation is determined by the highest derivative present in the equation.

Examining the equation, the derivatives present are:

dydx\frac{dy}{dx} (first derivative)

d2ydx2\frac{d^2y}{dx^2} (second derivative)


The highest derivative in the equation is the second derivative d2ydx2\frac{d^2y}{dx^2}.

The square roots and powers do not affect the order. Order only depends on the highest derivative present.


Therefore, the order of the differential equation is 22.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question