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The speed of water current is half the speed of a motor boat. The motor boat travels 15 km downstream in 1 hour. Then the time taken to return to the starting point is:

Solution

✅ Correct Option: 2

Let boat speed in still water =b= b km/h and current speed =c= c km/h.

The current speed is half the boat speed:

c=b2c = \dfrac{b}{2}


The boat travels 15 km downstream in 1 hour.

Downstream speed =DistanceTime= \dfrac{\text{Distance}}{\text{Time}}

=151= \dfrac{15}{1}

=15= 15 km/h


Downstream speed is the sum of boat speed and current speed:

b+c=15b + c = 15

Substituting c=b2c = \dfrac{b}{2}:

b+b2=15b + \dfrac{b}{2} = 15

2b+b2=15\dfrac{2b + b}{2} = 15

3b2=15\dfrac{3b}{2} = 15

3b=303b = 30

b=10b = 10 km/h

Therefore:

c=102=5c = \dfrac{10}{2} = 5 km/h


Upstream speed is the difference between boat speed and current speed:

Upstream speed =b−c= b - c

=10−5= 10 - 5

=5= 5 km/h


Time to return upstream:

Time =DistanceSpeed= \dfrac{\text{Distance}}{\text{Speed}}

=155= \dfrac{15}{5}

=3= 3 hours

Therefore, the time taken to return to the starting point is 3 hours.

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