CUET Mathematics - sqrt(16+( x)^2)x dx is equal to (where C is an arbitrary constant) | PYQs + Solutions

CUET Mathematics 2025 30 May Shift 2

Calculus

Hard

core

$2\log\left|\log x + \sqrt{16+(\log x)^2}\right| + \log x\sqrt{16+(\log x)^2} + C$

$16\log\left|\log x + \sqrt{16+(\log x)^2}\right| + \frac{\log x}{2}\sqrt{16+(\log x)^2} + C$

$8\log\left|\log x + \sqrt{16+(\log x)^2}\right| + \frac{\log x}{2}\sqrt{16+(\log x)^2} + C$

$4\log\left|\log x + \sqrt{16+(\log x)^2}\right| + \frac{\log x}{2}\sqrt{16+(\log x)^2} + C$

✅ Correct Option: 3

CUET Mathematics 2025 30 May Shift 2 PYQs