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If A=[1−12−1]A = \begin{bmatrix}1 & -1 \\ 2 & -1\end{bmatrix}, B=[a1b−1]B = \begin{bmatrix}a & 1 \\ b & -1\end{bmatrix} and (A+B)2=A2+B2(A + B)^2 = A^2 + B^2 then

Solution

✅ Correct Option: 1

(A+B)2=A2+AB+BA+B2(A + B)^2 = A^2 + AB + BA + B^2

Since matrix multiplication is not commutative, AB≠BAAB \neq BA in general, so the cross terms cannot be combined.

Given (A+B)2=A2+B2(A + B)^2 = A^2 + B^2, this means:

AB+BA=OAB + BA = O


AB=[1−12−1][a1b−1]AB = \begin{bmatrix}1 & -1 \\ 2 & -1\end{bmatrix}\begin{bmatrix}a & 1 \\ b & -1\end{bmatrix}

=[a−b22a−b3]= \begin{bmatrix}a - b & 2 \\ 2a - b & 3\end{bmatrix}


BA=[a1b−1][1−12−1]BA = \begin{bmatrix}a & 1 \\ b & -1\end{bmatrix}\begin{bmatrix}1 & -1 \\ 2 & -1\end{bmatrix}

=[a+2−a−1b−2−b+1]= \begin{bmatrix}a+2 & -a-1 \\ b-2 & -b+1\end{bmatrix}


AB+BA=[2a−b+21−a2a−24−b]=[0000]AB + BA = \begin{bmatrix}2a - b + 2 & 1 - a \\ 2a - 2 & 4 - b\end{bmatrix} = \begin{bmatrix}0 & 0 \\ 0 & 0\end{bmatrix}

From entry (1,2)(1,2):

1−a=01 - a = 0

a=1a = 1

From entry (2,2)(2,2):

4−b=04 - b = 0

b=4b = 4

From entry (2,1)(2,1):

2(1)−2=02(1) - 2 = 0 ✓

From entry (1,1)(1,1):

2(1)−4+2=02(1) - 4 + 2 = 0 ✓


a=1,b=4a = 1, \quad b = 4

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