The area of region bounded by the curve y^2 = 4ax and the straight line x = 2a, a > 0 in the first quadrant is: Option 1: 8a^3/3 sq. units Option 2: 8√2a^2/3 sq. units Option 3: 32a^3/3 sq. units Option 4: 64a^3/3 sq. units

Answer: 8√2a^2/3 sq. units. Solution: Solution Coming Soon

Calculus

Application of Integrals

Medium

core

The area of region bounded by the curve $y^2 = 4ax$ and the straight line $x = 2a$ , $a > 0$ in the first quadrant is:

$\frac{8a^3}{3}$ sq. units

$\frac{8\sqrt{2}a^2}{3}$ sq. units

$\frac{32a^3}{3}$ sq. units

$\frac{64a^3}{3}$ sq. units

✅ Correct Option: 2

Solution Coming Soon

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