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A company has been producing steel tubes of mean inner diameter of 2 cm. A sample of 10 tubes gives an inner diameter of 2.01 cm and a standard deviation of 0.063 cm. If t9(0.05)=2.262t_9(0.05)=2.262, then which of the following is NOT correct?

Solution

✅ Correct Option: 4

t=(xˉ−μ)n−1s=(2.01−2)×30.063≈0.476t=\frac{(\bar x-\mu)\sqrt{n-1}}{s}=\frac{(2.01-2)\times3}{0.063}\approx0.476, which is far below t9(0.05)=2.262t_9(0.05)=2.262. So the null hypothesis is accepted and the difference is not significant; the statement that it is significant is the incorrect one.

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