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For matrix A=[2−334]A = \begin{bmatrix} 2 & -3 \\ 3 & 4 \end{bmatrix} the value of A2−6AA^2 - 6A is equal to:(where I is an identity matrix of order 2)

Solution

✅ Correct Option: 2

A2=[−5−18187]A^2=\begin{bmatrix}-5&-18\\18&7\end{bmatrix} and 6A=[12−181824]6A=\begin{bmatrix}12&-18\\18&24\end{bmatrix}.

Subtracting, A2−6A=[−1700−17]=−17IA^2-6A=\begin{bmatrix}-17&0\\0&-17\end{bmatrix}=-17I.

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