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If f(x)=x3+px2+qx−3f(x) = x^3 + px^2 + qx - 3 has a local maxima at x=0x = 0 and local minima at x=1x = 1, then the values of pp and qq respectively, are:

Solution

✅ Correct Option: 2

f′(x)=3x2+2px+qf'(x)=3x^2+2px+q must vanish at x=0x=0 and x=1x=1.

f′(0)=q=0f'(0)=q=0 and f′(1)=3+2p+q=0f'(1)=3+2p+q=0 give p=−32p=-\dfrac32.

So p=−32p=-\dfrac32, q=0q=0.

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