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For a given line L: x2=y+13=−z−3−5\dfrac{x}{2}=\dfrac{y+1}{3}=\dfrac{-z-3}{-5}, which of the following is/are True ?

(A) The direction ratio of line L is (2, 3, -5)

(B) The perpendicular distance of the point (1, 1, 3) on the line L is 3\sqrt{3}

(C) The foot of perpendicular from the point (1, 1, 3) on line L is (2, 2, 1)

(D) The image of point (1, 1, 3) with respect to line L is (3, 3, 1)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

The line is x2=y+13=z+35\dfrac{x}{2}=\dfrac{y+1}{3}=\dfrac{z+3}{5}, so direction ratios are (2,3,5)(2,3,5) and (A) fails. For a general point (2t,3t−1,5t−3)(2t,3t-1,5t-3), perpendicularity from (1,1,3)(1,1,3) gives 38t=3838t=38, so t=1t=1 and the foot is (2,2,2)(2,2,2), making (C) false. The distance is 1+1+1=3\sqrt{1+1+1}=\sqrt3 and the image is (3,3,1)(3,3,1).

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