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Match List-I with List-II

List-IList-II
(A) Equations of line through (5,−4,6)(5, -4, 6) with direction ratios 3,7,23, 7, 2(I) x+35=y+7−4=z+26\frac{x+3}{5} = \frac{y+7}{-4} = \frac{z+2}{6}
(B) Equations of line through (3,7,2)(3, 7, 2) with direction ratios 5,−4,65, -4, 6(II) x−35=y−7−4=z−26\frac{x-3}{5} = \frac{y-7}{-4} = \frac{z-2}{6}
(C) Equations of line through (−5,4,−6)(-5, 4, -6) with direction ratios 3,7,23, 7, 2(III) x−53=y+47=z−62\frac{x-5}{3} = \frac{y+4}{7} = \frac{z-6}{2}
(D) Equations of line through (−3,−7,−2)(-3, -7, -2) with direction ratios 5,−4,65, -4, 6(IV) x+53=y−47=z+62\frac{x+5}{3} = \frac{y-4}{7} = \frac{z+6}{2}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

The equation of a line passing through a point (x1,y1,z1)(x_1, y_1, z_1) with direction ratios a,b,ca, b, c is given by:

x−x1a=y−y1b=z−z1c\frac{x - x_1}{a} = \frac{y - y_1}{b} = \frac{z - z_1}{c}


For line through (5,−4,6)(5, -4, 6) with direction ratios 3,7,23, 7, 2:

x1=5x_1 = 5, y1=−4y_1 = -4, z1=6z_1 = 6

a=3a = 3, b=7b = 7, c=2c = 2

x−53=y−(−4)7=z−62\frac{x - 5}{3} = \frac{y - (-4)}{7} = \frac{z - 6}{2}

x−53=y+47=z−62\frac{x - 5}{3} = \frac{y + 4}{7} = \frac{z - 6}{2}

This matches (III)


For line through (3,7,2)(3, 7, 2) with direction ratios 5,−4,65, -4, 6:

x1=3x_1 = 3, y1=7y_1 = 7, z1=2z_1 = 2

a=5a = 5, b=−4b = -4, c=6c = 6

x−35=y−7−4=z−26\frac{x - 3}{5} = \frac{y - 7}{-4} = \frac{z - 2}{6}

This matches (II)


For line through (−5,4,−6)(-5, 4, -6) with direction ratios 3,7,23, 7, 2:

x1=−5x_1 = -5, y1=4y_1 = 4, z1=−6z_1 = -6

a=3a = 3, b=7b = 7, c=2c = 2

x−(−5)3=y−47=z−(−6)2\frac{x - (-5)}{3} = \frac{y - 4}{7} = \frac{z - (-6)}{2}

x+53=y−47=z+62\frac{x + 5}{3} = \frac{y - 4}{7} = \frac{z + 6}{2}

This matches (IV)


For line through (−3,−7,−2)(-3, -7, -2) with direction ratios 5,−4,65, -4, 6:

x1=−3x_1 = -3, y1=−7y_1 = -7, z1=−2z_1 = -2

a=5a = 5, b=−4b = -4, c=6c = 6

x−(−3)5=y−(−7)−4=z−(−2)6\frac{x - (-3)}{5} = \frac{y - (-7)}{-4} = \frac{z - (-2)}{6}

x+35=y+7−4=z+26\frac{x + 3}{5} = \frac{y + 7}{-4} = \frac{z + 2}{6}

This matches (I)


Therefore, the correct matching is:

(A) → (III), (B) → (II), (C) → (IV), (D) → (I)

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