Skip to main contentSkip to solution

Two ships are sailing in the sea on the two sides of a lighthouse. The angles of elevation of the top of the lighthouse as observed from two ships are 30° and 45°, respectively. If the lighthouse is 100 m high, the distance between two ships is approximately:

Solution

✅ Correct Option: 3
Solution figure for JIPMAT 2025 QA question 26 (Geometry)

Let Ship A and Ship B have the angle of elevation 45∘45^\circ and 30∘30^\circ, respectively.

Let their distance from the lighthouse be xx and yy respectively.

We know, height of lighthouse =100= 100 meters

For xx:

tan⁡(45∘)=OppositesideAdjacentSide\tan (45^\circ) = \frac{Opposite side}{Adjacent Side}

1=100x1= \frac{100}{x}

x=100x = 100 meters

For yy:

tan⁡(30∘)=OppositesideAdjacentSide\tan (30^\circ) = \frac{Opposite side}{Adjacent Side}

13=100y\frac{1}{\sqrt3}= \frac{100}{y}

y=100×3y = 100\times \sqrt3

y=100×1.732y = 100\times 1.732

y=173.2y = 173.2 meters

Hence, distance between the two ships =x+y=100+173=273= x + y = 100 + 173 = 273 meters.

Thus, the correct option is Option 3.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question