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Cost price of article A is ₹ 200 more than the cost price of article B. Article A was sold at 10% loss and article B was sold at 25% profit. If the overall profit earned after selling both the articles is 4%, then what is the cost price of article B?

Solution

✅ Correct Option: 2

Let the cost price of article B be xx

Then, the cost price of article A is (x+200)(x +200)

Article A is sold at 10%10\% loss, so Seling Price of A =(x+200)×0.90=0.9x+180= (x+200) \times 0.90 = 0.9x + 180

Article B is sold at 25%25 \% profit, so Selling Price of B =1.25x= 1.25x

The total cost price =x+(x+200)=2x+200= x+(x+200)=2 x+200

Total selling price =0.9x+180+1.25x= 0.9x + 180 +1.25x

Also, overall profit is 4%4 \%, so total selling price =(2x+200)×1.04(2 x+ 200) \times 1.04

Thus, we get Selling Price: 0.9x+180+1.25x=1.04(2x+200)0.9x + 180+1.25 x=1.04(2 x+200)

180+2.15x=2.08x+208180+2.15 x=2.08x + 208

0.07x=280.07x = 28

x=400x = 400

Hence, the correct answer is Option 2.

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