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Given below are two statement:

Statement I: If sin⁡(θ)=513\sin (\theta)=\frac{5}{13}, then the value of tan⁡(θ)=512\tan (\theta)=\frac{5}{12}

Statement II: if cot⁡(θ)=125\cot (\theta)=\frac{12}{5}, then the value of sin⁡(θ)=512\sin (\theta)=\frac{5}{12}

In the light of the above statements, choose the correct answer form the question below:

Solution

✅ Correct Option: 3

Statement I: If sin⁡(θ)=513\sin(\theta) = \frac{5}{13}

In right triangle: sin⁡2(θ)+cos⁡2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1

(513)2+cos⁡2(θ)=1(\frac{5}{13})^2 + \cos^2(\theta) = 1

cos⁡2(θ)=1−25169=144169\cos^2(\theta) = 1 - \frac{25}{169} = \frac{144}{169}

cos⁡(θ)=1213\cos(\theta) = \frac{12}{13}

Therefore tan⁡(θ)=sin⁡(θ)cos⁡(θ)=513×1312=512\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} = \frac{5}{13} × \frac{13}{12} = \frac{5}{12} ✓

Statement II: If cot⁡(θ)=125\cot(\theta) = \frac{12}{5}

cot⁡(θ)=cos⁡(θ)sin⁡(θ)=125\cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)} = \frac{12}{5}

Therefore sin⁡(θ)=513\sin(\theta) = \frac{5}{13} (using sin⁡2(θ)+cos⁡2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1 again)

Not equal to 512\frac{5}{12} ✗

Therefore, Statement I is true and Statement II is false.

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