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The value of 99917+99927+99937+99947+99957+99967999\frac{1}{7} + 999\frac{2}{7} + 999\frac{3}{7} + 999\frac{4}{7} + 999\frac{5}{7} + 999\frac{6}{7} is equal to :

Solution

✅ Correct Option: 1

Basic learning:

1+0.5=1.51 + 0.5 = 1.5

This can be written as a fraction:

1.5=1121.5 = 1 \frac{1}{2}

This can also be written as:

112=1+12 1 \frac{1}{2} = 1 + \frac{1}{2}


Hence, question states:

99917+99927+99937+99947+99957+99967999\frac{1}{7} + 999\frac{2}{7} + 999\frac{3}{7} + 999\frac{4}{7} + 999\frac{5}{7} + 999\frac{6}{7}

This can be written as:

999+17+999+27+999+37+999+47+999+57+999+67999 + \frac{1}{7} + 999 + \frac{2}{7} + 999 + \frac{3}{7} + 999 + \frac{4}{7} + 999 + \frac{5}{7} + 999 + \frac{6}{7}

We can add the fractions separately. Also, 999999 appears six times:

⇒6×999+(17+27+37+47+57+67)\Rightarrow 6 \times 999 + \left( \frac{1}{7} + \frac{2}{7} + \frac{3}{7} + \frac{4}{7} + \frac{5}{7} + \frac{6}{7} \right)

⇒5994+(17+27+37+47+57+67)\Rightarrow 5994 + \left( \frac{1}{7} + \frac{2}{7} + \frac{3}{7} + \frac{4}{7} + \frac{5}{7} + \frac{6}{7} \right)

⇒5994+217\Rightarrow 5994 + \frac{21}{7}

⇒5994+3=5997\Rightarrow 5994 + 3 = \boxed{5997}

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