If a + b = 2c, then the value of a/(a-c) + b/(b-c) is Option 1: 1/2 Option 2: 1 Option 3: 2 Option 4: 3

Answer: 2. Solution: While one can try solving this by simplifying the expression, the easiest way is to assume random values. Let a = 3 and b = 5 Thus, a + b = 3 + 5 = 8 = 2c arrow c= 4 Now, a/(a-c) + b/(b-c) = 3/(3-4) + 5/(5-4)= 3/(-1) + 5/1 = -3+5 = 2 Now, let's verify with one more case. Let a = 3 and b = 7 Thus, a + b = 3 + 7 = 10 = 2c arrow c= 5 Now, a/(a-c) + b/(b-c) = 3/(3-5) + 7/(7-5)= 3/(-2) + 7/2 = -1.5+3.5 = 2 Hence, the correct option is Option 3.

Algebra

Linear Equation

Medium

If $a + b = 2c$ , then the value of $\frac{a}{a-c} + \frac{b}{b-c}$ is

$\frac{1}{2}$

✅ Correct Option: 3

While one can try solving this by simplifying the expression, the easiest way is to assume random values.

Let $a = 3$ and $b = 5$

Thus, $a + b = 3 + 5 = 8 = 2c \rightarrow c= 4$

Now, $\frac{a}{a-c} + \frac{b}{b-c} = \frac{3}{3-4} + \frac{5}{5-4}= \frac{3}{-1} + \frac{5}{1} = -3+5 = 2$

Now, let's verify with one more case.

Let $a = 3$ and $b = 7$

Thus, $a + b = 3 + 7 = 10 = 2c \rightarrow c= 5$

Now, $\frac{a}{a-c} + \frac{b}{b-c} = \frac{3}{3-5} + \frac{7}{7-5}= \frac{3}{-2} + \frac{7}{2} = -1.5+3.5 = 2$

Hence, the correct option is Option 3.

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If a+b=2ca + b = 2ca+b=2c, then the value of aa−c+bb−c\frac{a}{a-c} + \frac{b}{b-c}a−ca​+b−cb​ is

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If $a + b = 2c$ , then the value of $\frac{a}{a-c} + \frac{b}{b-c}$ is