A speaks truth in 75% cases and B in 80% of the cases. In what percentage of cases are they likely to contradict each other, in narrating the same incident?

Sam can hit a target 1 time in 4 shots, Jack can hit the target 2 times in 4 shots and Raj can hit the target 6 times in 6 shots. What is the probability that at least 2 shots hit the target?

Let A and B be two events such that P(A)=0.25, P(B)=0.50 and P(A ∩ B)=0.14. The probability that neither A nor B occurs is:

Four persons are chosen at random from a group of 3 men, 2 women and 4 children. The chance that exactly 2 of them are children is:

A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap. If three caps are picked at random without replacement, what is the probability that two are red and one is green?

Given below are two statements in the context of throwing two different dice together:

Statement (I): The probability that the two numbers obtained have an even sum is 0.50.

Statement (II): The probability that the two numbers obtained have an even product is 0.75.

In light of the above statements, choose the most appropriate answer from the options given below.

A speaks the truth in $75 \%$ cases and $B$ in $80 \%$ of the cases. In what percentage of cases are they likely to contradict each other in narrating the same incident?