Skip to main contentSkip to solution

Four persons are chosen at random from a group of 3 men, 2 women and 4 children. The chance that exactly 2 of them are children is:

Solution

✅ Correct Option: 4

Total number of ways to choose 44 people from 9: 9C4=126^{9}C_{4}=126

Favorable outcomes = selecting 22 children and 22 others (from adults: 33 men + 22 women = 55 adults)

Ways to choose 22 children from 4: 4C2=6^{4}C_{2}=6

Ways to choose 22 adults from 55 : 5C2=10^{5}C_{2}=10

Total favorable =6×10=60=6 \times 10=60

Probability=60126=1021= \frac{60}{126}=\frac{10}{21}

Hence, the correct option is Option 4.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question