Amit and Alok attempted to solve a quadratic equation. Amit made a mistake in writing down the constant term and ended up with roots $(4, 3)$. Alok made a mistake in writing down coefficient of $x$ to get roots $(3, 2)$. The correct roots of the equation are:

For equation: $ax^2+bx+c=0$

Sum of roots $=-\frac{b}{a}$

Product of roots $= \frac{c}{a}$

Let's assume the equation here to be $x^2+bx+c=0$, we need not worry ourself with the value of $a$ as it doesn't matter here!

Amit got the constant term wrong, but he has gotten the coefficient of $x$ right.

So from his equation, we can derive $-b=4+3=7 \Rightarrow \boxed{-b=7}$

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Similarly, Alok has gotten the coefficient of $x$ wrong, but he has gotten the constant term right.

So from his equation, we can derive $c=3\times2=6 \Rightarrow \boxed{c=6}$

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Now we know sum of roots is $7$ and product of roots is $6$.

We can go through the options to see what matches these (add both the numbers for sum of roots; multiply both the numbers for product).

Roots as per Option 2: $(6,1)$

Sum $= 6+1 = 7$

Product $= 6 \times 1 = 6$