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The ratios of copper to zinc in alloys A and B are 3:4 and 5:9, respectively. If A and B are taken in ratio 2:3 and melted to form new alloy C, then the ratio of copper to zinc in C is:

Solution

✅ Correct Option: 4
Copper
Alloy AAlloy B

37\frac{3}{7}

514\frac{5}{14}

2 parts3 parts

635+1570=2770\frac{6}{35}+ \frac{15}{70} = \frac{27}{70}

You can solve, Zinc =1−2770=4370=1 - \frac{27}{70} = \frac{43}{70}

Alternatively:

Zinc
Alloy AAlloy B

47\frac{4}{7}

914\frac{9}{14}

2 parts3 parts

835+2770=4370\frac{8}{35}+ \frac{27}{70} = \frac{43}{70}

Therefore, the ratio of copper to zinc in alloy C is 27:43.

Hence, the correct option is Option 4.

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