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The traffic lights at three different road crossings change after every 48 sec, 72 sec and 108 sec, respectively. They all change simultaneously at 08:20:00 hours, when will they again change simultaneously?

Solution

✅ Correct Option: 2

Required time =LCM=\mathrm{LCM} of 48 , 72 and 108 seconds

248,72,108224,36,54212,18,2736,9,2732,3,92,1,3\begin{array}{c|ccc} 2 & 48,72,108 \\ \hline 2 & 24,36,54 \\ \hline 2 & 12,18,27 \\ \hline 3 & 6,9,27 \\ \hline 3 & 2,3,9 \\ \hline & 2,1,3 \end{array}

LCM =2×2×2×2×3×3×3=2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 =432=432 seconds =7=7 minutes 1212 seconds

∴\therefore They will beep after 7 minutes and 12 seconds together so after 8:20:00 hours, they will beat together at 8:27:12 hours.

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