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There are 50 telephone lines in an exchange. If the probability that any one of them will be busy is 0.1, then the probability that all the lines are busy is

Solution

✅ Correct Option: 2

With n=50n=50 and p=0.1p=0.1, use the Poisson approximation with λ=np=5\lambda = np = 5.

P(X=50)=e−λλ5050!=550e−550!P(X=50) = \frac{e^{-\lambda}\lambda^{50}}{50!} = \frac{5^{50}e^{-5}}{50!}.

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