If the function f(x)=casese^2_e x^2-1x-1, & x 1\\ a, & x=1cases is continuous at x=1, then the value of a is: Option 1: 1 Option 2: 2 Option 3: 4 Option 4: _e 2

The answer is '4'. View full solution:

CUET Mathematics - If the function f(x)=casese^2_e x^2-1x-1, & x 1\\ a, & x=1cases is continuous at x=1, then the value of a is: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 2

Calculus

Medium

core

$\log_e 2$

✅ Correct Option: 3

Related questions:

19th May Shift 1

At $x = 2$ , $f(x) = [x]$ is

[where [.] is greatest integer function]

13 May Shift 1

Match List-I with List-II

List-I	List-II
Function	Property
(A) $f(x) = \begin{cases} \frac{x}{\vert x \vert} & : x \neq 0 \\ 0 & : x = 0 \end{cases}$	(I) continuous but not differentiable at $x= 0$
(B) $f(x) = \vert x \vert$	(II) continuous but not differentiable at $x=1$
(C) $f(x) = \vert x^2 - 1 \vert$	(III) discontinuous at $x = 0$
(D) $f(x) = \vert x - 1 \vert$	(IV) continuous but not differentiable at $x = 1, -1$

Choose the correct answer from the options given below:

15 June Shift 2

The points of discontinuity of the function f defined by $f(x) = \begin{cases} x+2 & x \leq 1 \\ x-2 & 1 < x < 2 \\ 0 & x \geq 2 \end{cases}$ are :