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Match List-I with List-II

List-IList-II
(A) ddx(sin⁡x)\frac{d}{dx}(\sqrt{\sin x})(I) −sin⁡x2cos⁡x\frac{-\sin x}{2\sqrt{\cos x}}
(B) ddx(cos⁡x)\frac{d}{dx}(\sqrt{\cos x})(II) −sin⁡2x-\sin 2x
(C) ddx(sin⁡2x)\frac{d}{dx}(\sin^2 x)(III) cos⁡x2sin⁡x\frac{\cos x}{2\sqrt{\sin x}}
(D) ddx(cos⁡2x)\frac{d}{dx}(\cos^2 x)(IV) sin⁡2x\sin 2x

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

Apply the chain rule.

(A) cos⁡x2sin⁡x\frac{\cos x}{2\sqrt{\sin x}}, (III).

(B) −sin⁡x2cos⁡x\frac{-\sin x}{2\sqrt{\cos x}}, (I).

(C) 2sin⁡xcos⁡x=sin⁡2x2\sin x\cos x=\sin2x, (IV).

(D) −2cos⁡xsin⁡x=−sin⁡2x-2\cos x\sin x=-\sin2x, (II).

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