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Let y(x)y(x) be the solution curve of the differential equation

dydx+2y2=0,y(1)=1\frac{dy}{dx} + 2y^2 = 0, y(1) = 1, then y(34)y\left(\frac{3}{4}\right) is equal to:

Solution

✅ Correct Option: 3

Separate variables: dyy2=−2 dx\frac{dy}{y^2}=-2\,dx, so 1y=2x+C\frac{1}{y}=2x+C. Using y(1)=1y(1)=1 gives C=−1C=-1, hence 1y=2x−1\frac{1}{y}=2x-1. At x=34x=\frac{3}{4}, 1y=12\frac{1}{y}=\frac{1}{2}, so y=2y=2.

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