The value of _(-/2)^(/2)(, x, +, x, )dx equals: Option 1: 1 Option 2: 2 Option 3: 3 Option 4: 4

Answer: 4. Solution: The integrand is even, so the integral =2_0^(/2)( x+ x)dx=2[ x- x]_0^(/2)=2[1-(-1)]=4.

Calculus

Integrals

Easy

core

The value of $\int_{-\pi/2}^{\pi/2}(\sin|x|+\cos|x|)dx$ equals:

✅ Correct Option: 4

The integrand is even, so the integral $=2\int_0^{\pi/2}(\sin x+\cos x)dx=2[\sin x-\cos x]_0^{\pi/2}=2[1-(-1)]=4$ .

2026: 31 May Shift 2

The value of $\displaystyle\int_{\pi/6}^{\pi/3} \dfrac{\sin x+\cos x}{\sqrt{\sin 2x}}\,dx$ is:

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$\int \frac{dx}{x^3\sqrt{(1 + x^4)}} =$

2026: 19 May Shift 1

The value of integral $I = \int_{3}^{5} \frac{x^2}{(x-1)(x-2)}\,dx$ is

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$\int_0^2 x(2-x)^n dx$ is equal to

2025: 30 May Shift 2

The value of $\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} (\sin|x| + \cos|x|)dx$ , is equal to:

2025: 30 May Shift 2

$\int \frac{1}{x(x^5-1)} dx$ is equal to