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If A=[1221]A=\begin{bmatrix}1 & 2\\2 & 1\end{bmatrix} and f(x)=x2−2x−3f(x)=x^2-2x-3, then f(A)f(A) is equal to

Solution

✅ Correct Option: 2

A2=[5445]A^2=\begin{bmatrix}5&4\\4&5\end{bmatrix}, so f(A)=A2−2A−3I=[5445]−[2442]−[3003]=Of(A)=A^2-2A-3I=\begin{bmatrix}5&4\\4&5\end{bmatrix}-\begin{bmatrix}2&4\\4&2\end{bmatrix}-\begin{bmatrix}3&0\\0&3\end{bmatrix}=O.

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