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A box contains 8 red and 2 white balls. If three balls are drawn, one by one, at random without replacement, then the variance of the number of white balls drawn is:

Solution

✅ Correct Option: 1

With (103)=120\binom{10}{3}=120: P(0)=56120=715P(0)=\frac{56}{120}=\frac{7}{15}, P(1)=56120=715P(1)=\frac{56}{120}=\frac{7}{15}, P(2)=8120=115P(2)=\frac{8}{120}=\frac{1}{15}. Then E(X)=35E(X)=\frac35 and E(X2)=715+415=1115E(X^2)=\frac{7}{15}+\frac{4}{15}=\frac{11}{15}, so Var =1115−925=2875=\frac{11}{15}-\frac{9}{25}=\frac{28}{75}.

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