Match the LIST-I with LIST-II, LIST-I (Inequality), LIST-II (Solution Set), A., 3x-5 ≥ 4, I., (-∞,-1] [7/3,∞), B., 3x ≥ 6-3x, II., (-∞,-4] [2,∞), C., x+1 ≥ 3, III., [1,∞), D., 2-3x ≥ 5, IV., (-∞,1/3] [3,∞), Choose the correct answer from the options given below: Option 1: A-I, B-II, C-III, D-IV Option 2: A-II, B-I, C-III, D-IV Option 3: A-III, B-IV, C-I, D-II Option 4: A-IV, B-III, C-II, D-I

Answer: A-IV, B-III, C-II, D-I. Solution: A: 3x-5≥4 or ≤-4 gives x≤13 or x≥3. B: squaring gives 36x≥36, i.e. x≥1. C: x≤-4 or x≥2. D: x≤-1 or x≥73.

Algebra

Inequalities

Medium

applied

Match the LIST-I with LIST-II

LIST-I
(Inequality) LIST-II
(Solution Set)
A. $\vert 3x-5 \vert \geq 4$ I. $(-\infty,-1] \cup \left[\dfrac{7}{3},\infty\right)$
B. $\vert 3x \vert \geq \vert 6-3x \vert$ II. $(-\infty,-4] \cup [2,\infty)$
C. $\vert x+1 \vert \geq 3$ III. $[1,\infty)$
D. $\vert 2-3x \vert \geq 5$ IV. $\left(-\infty,\dfrac{1}{3}\right] \cup [3,\infty)$

Choose the correct answer from the options given below:

	LIST-I (Inequality)		LIST-II (Solution Set)
A.	$\vert 3x-5 \vert \geq 4$	I.	$(-\infty,-1] \cup \left[\dfrac{7}{3},\infty\right)$
B.	$\vert 3x \vert \geq \vert 6-3x \vert$	II.	$(-\infty,-4] \cup [2,\infty)$
C.	$\vert x+1 \vert \geq 3$	III.	$[1,\infty)$
D.	$\vert 2-3x \vert \geq 5$	IV.	$\left(-\infty,\dfrac{1}{3}\right] \cup [3,\infty)$

A-I, B-II, C-III, D-IV

A-II, B-I, C-III, D-IV

A-III, B-IV, C-I, D-II

A-IV, B-III, C-II, D-I

✅ Correct Option: 4

A: $3x-5\ge4$ or $\le-4$ gives $x\le\frac13$ or $x\ge3$ . B: squaring gives $36x\ge36$ , i.e. $x\ge1$ . C: $x\le-4$ or $x\ge2$ . D: $x\le-1$ or $x\ge\frac73$ .

2026: 31 May Shift 2

The solution set $\{x: x \in R, 3x-2 < x+2 \le 2x+6\}$ (Where $R$ is set of real numbers) is :

2025: 2 June Shift 1

Solution of the inequality $\frac{2x+3}{4x-5} \geq 0$ is

2026: 25 May Shift 1

If $\dfrac{x+3}{2x-1} < 1$ , then the solution set contains :

A. $(-\infty,1/2)$

B. $(-\infty,4)$

C. $(-4,4)$

D. $(4,\infty)$

Choose the correct answer from the options given below:

2025: 15 May Shift 1

The inequality $\frac{5x - 2}{3} - \frac{7x - 3}{5} > \frac{x}{4}$ holds when

2026: 30 May Shift 2

The solution set of the inequality $3x+4y<12$ is

2025: 13 May Shift 1

If $a, b$ and $c$ are positive real numbers, then

Match List-I with List-II

List-I	List-II
(Expression)	(The Least value of the expression)
(A) $(a + b)(b + c)(c + a)$	(I) $8abc$
(B) $(a + b + c)(ab + bc + ca)$	(II) $9a^2b^2c^2$
(C) $(a^2b + b^2c + c^2a)(ab^2 + bc^2 + ca^2)$	(III) $9abc$
(D) $(a + b)^2(b + c)^2(c + a)^2$	(IV) $64a^2b^2c^2$

Choose the correct answer from the options given below:

Solution

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