The value (/s) of $x$ satisfying the matrix equation:

$x\begin{bmatrix}2x & 2\\3 & x\end{bmatrix}+2\begin{bmatrix}8 & 5x\\4 & 4x\end{bmatrix}=2\begin{bmatrix}(x^2+8) & 24\\10 & 6x\end{bmatrix}$ is/are:

If $A = \begin{bmatrix} 0 & 1 & -3 \\ -1 & 0 & 5 \\ 3 & -5 & 0 \end{bmatrix}$, then the value of $|A^{2025}|$ is

If $A$ is an invertible matrix of order 3, then

Match List-I with List-II

Choose the correct answer from the options given below:

If $A = \begin{bmatrix}\frac{1}{4} & 2\\0 & 2x-3\end{bmatrix}$, $B = \begin{bmatrix}4 & 8\\0 & -1\end{bmatrix}$ and AB = $I_2$ (Identity matrix of order 2), then the value of $x$ is

If $\left[\begin{array}{cc}5 x+8 & 7 \\ y+3 & 10 x+12\end{array}\right]=\left[\begin{array}{cc}2 & 3 y+1 \\ 5 & 0\end{array}\right]$, then the value of $5 x+3 y$ is equal to :

If $A=\begin{bmatrix} 2 & 1 \\ 7 & 5 \end{bmatrix}$, then the value of $|A(adj A)|$ is

If A is a square matrix of order 3 and |A| = -5, then |3A| is equal to