CUET Mathematics - The vector equation of line passing through (-1, 3, -2) and perpendicular to the lines x+4/1 = y/2 = z-3/3 and x+2/-3 = y+5/2 = z-6/5 is | PYQs + Solutions

CUET Mathematics 2025 3 June Shift 2

Geometry

Medium

core

$\vec{r} = (-3\hat{i} + 4\hat{j} + 15\hat{k}) + \lambda(-i + 3\hat{j} - 2\hat{k})$

$\vec{r} = (-\hat{i} + 3\hat{j} - 2\hat{k}) + \lambda(-3\hat{i} + \hat{4j} + 15\hat{k})$

$\vec{r} = 2\hat{i} - 7\hat{j} + 4\hat{k} + \lambda(-i + 3\hat{j} - 2\hat{k})$

$\vec{r} = (-i + 3\hat{j} - 2\hat{k}) + \lambda(2\hat{i} - 7\hat{j} + 4\hat{k})$

✅ Correct Option: 4

CUET Mathematics 2025 3 June Shift 2 PYQs