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If A is an invertible matrix, then which of the following statement(s) is/are TRUE?

(A) ∣A−1∣=∣A∣|A^{-1}| = |A|

(B) (A−1)−1=A(A^{-1})^{-1} = A

(C) A−1=adjA∣A∣A^{-1} = \frac{adj A}{|A|}

(D) (AT)−1=(A−1)T(A^T)^{-1} = (A^{-1})^T

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

For an invertible matrix AA, checking each statement:

A×A−1=IA \times A^{-1} = I

Taking determinant of both sides:

∣A∣×∣A−1∣=∣I∣|A| \times |A^{-1}| = |I|

∣A∣×∣A−1∣=1|A| \times |A^{-1}| = 1

∣A−1∣=1∣A∣|A^{-1}| = \frac{1}{|A|}

Since ∣A−1∣=1∣A∣|A^{-1}| = \frac{1}{|A|} and not ∣A∣|A|, statement (A) is FALSE.


If A−1A^{-1} is the inverse of AA, then AA is the inverse of A−1A^{-1}.

By definition of inverse:

(A−1)−1=A(A^{-1})^{-1} = A

Statement (B) is TRUE.


For an invertible matrix, the inverse formula is:

A−1=adjA∣A∣A^{-1} = \frac{adj A}{|A|}

This is a standard property of invertible matrices.

Statement (C) is TRUE.


Starting with A×A−1=IA \times A^{-1} = I, taking transpose of both sides:

(A×A−1)T=IT(A \times A^{-1})^T = I^T

Using (AB)T=BTAT(AB)^T = B^T A^T:

(A−1)T×AT=I(A^{-1})^T \times A^T = I

This means (A−1)T(A^{-1})^T is the inverse of ATA^T.

Therefore:

(AT)−1=(A−1)T(A^T)^{-1} = (A^{-1})^T

Statement (D) is TRUE.


Statements (B), (C), and (D) are TRUE.

Statement (A) is FALSE.

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