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A cylinder with height 'h' and radius of base is 'r' which is open at the top having a given outer surface area, then volume of the cylinder is maximum if

Solution

✅ Correct Option: 3

With the top open, S=πr2+2πrhS=\pi r^2+2\pi rh is fixed, so h=S−πr22πrh=\dfrac{S-\pi r^2}{2\pi r} and V=πr2h=Sr−πr32V=\pi r^2h=\dfrac{Sr-\pi r^3}{2}. Setting dVdr=S−3πr22=0\dfrac{dV}{dr}=\dfrac{S-3\pi r^2}{2}=0 gives S=3πr2S=3\pi r^2. Substituting back, 2πrh=2πr22\pi rh=2\pi r^2, so h=rh=r.

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